- #1

foozeball2468

- 10

- 0

New question: Answer the previous question when the floor slopes upward at an angle of 5 degrees, and you push parallel to the floor.

Fa=(coefficient of friction)(mg)

P=(F) (v)

W=(F) (delta x)

My attempt is W=(95kg)(9.81m/s^2)(11m)(sin5 +cos5(.78))= 8.81 x10^3 J so solving for power I would use Work/17.74= 496 Watts

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A different route is P=(.78)(95kg)(9.8m/s^2)(cos5)(.62)=448 W

(solving for t I get 11m/.62m/s=17.74 s) so W=448x17.74 which is 7.96 x10^3 J

-both of these answers are smaller so I do not believe this is true

I am unsure if either of these is right and if both are wrong where have I gone wrong! thank you