(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 3.70 s, it is at point (4.30 m, 5.50 m) with velocity (3.10 m/s)j and acceleration in the positive x direction. At time t2 = 13.0 s, it has velocity (–3.10 m/s)i and acceleration in the positive y direction. What are the (a)x and (b)y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.

2. Relevant equations

I honestly do not know... Anything to do with circular motion I guess.

3. The attempt at a solution

270degrees=4.712 radians

w=angular velocity

w=theta/t

w=4.712/(13-3.7)

w=.5066rad/s

ac=centripetal acceleration

ac=v^2/r

r=v^2/ac

r=3.10^2/ac

r=9.61/ac

ac=r*alpha

ac=r*(w/t)

ac=r*(.5066/(13-3.7))

r=9.61/(.5066r/9.3)

r=89.373/.5066r

r^2=176.41

r=13.28

so 4.3+13.28=17.58 and y would remain 5.5 y (add radius to x, y would remain same as it just is to the direct right of point 1)

17.58 is WRONG

5.5 is RIGHT

I don't get how to solve for r when you don't know ac.

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# Homework Help: Finding the radius based on time and velocit

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