1. The problem statement, all variables and given/known data A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 3.70 s, it is at point (4.30 m, 5.50 m) with velocity (3.10 m/s)j and acceleration in the positive x direction. At time t2 = 13.0 s, it has velocity (–3.10 m/s)i and acceleration in the positive y direction. What are the (a)x and (b)y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit. 2. Relevant equations I honestly do not know... Anything to do with circular motion I guess. 3. The attempt at a solution 270degrees=4.712 radians w=angular velocity w=theta/t w=4.712/(13-3.7) w=.5066rad/s ac=centripetal acceleration ac=v^2/r r=v^2/ac r=3.10^2/ac r=9.61/ac ac=r*alpha ac=r*(w/t) ac=r*(.5066/(13-3.7)) r=9.61/(.5066r/9.3) r=89.373/.5066r r^2=176.41 r=13.28 so 4.3+13.28=17.58 and y would remain 5.5 y (add radius to x, y would remain same as it just is to the direct right of point 1) 17.58 is WRONG 5.5 is RIGHT I don't get how to solve for r when you don't know ac.