Finding the Rate of Climb for a Plane

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The discussion focuses on calculating the rate of climb for a plane that takes off at 88 km/h and climbs to clear a power line 15 meters high, 460 meters away. The key to solving the problem is understanding that "rate of climb" refers to the vertical component of the plane's velocity. To find this, one must first determine the angle of the plane's trajectory relative to the horizontal. Once the angle is established, calculating the rate of climb becomes straightforward. The original poster successfully resolved the issue after clarifying their understanding of the problem.
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I am having trouble with problem:

A plane needs 300 m to take off while going 88km/h. It then climbs with a constant speed of 88 km/h along a straight line, just celaring a power line 15m high at a horizontal distance of 460 m from it initial position.

I am asked to find the rate of climb of the plane.

I have figured out how to get the acceleration with

(Vf^2 - Vi^2)/2d a

but I do not know where to go from here.
 
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Note: I've moved this from Advanced Physics to Introductory Physics.

A plane needs 300 m to take off while going 88km/h. It then climbs with a constant speed of 88 km/h along a straight line, just celaring a power line 15m high at a horizontal distance of 460 m from it initial position.

I am asked to find the rate of climb of the plane.

The first thing that you need to recognize is that "rate of climb" means the same thing as "y-component of velocity while climbing". So the first thing you need to do is the angle that the plane's straight line trajectory makes with the horizontal. Since they give you the speed along that straight line tracjectory, finding the rate of climb should be easy after you get the angle.
 
thanx i figured it out waasn't thinking clearly much easier thn what i was making it
 
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