Finding the Solution for x in a Fractional Equation

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To solve the fractional equation x/m - 1/n = 3x/mn, the goal is to isolate x by moving all x terms to one side. Multiplying through by mn helps eliminate the fractions, leading to the equation xn - m = 3x. This can be rearranged to x(n - 3) = m, allowing for x to be factored out. The confusion about finding a common denominator is clarified by recognizing that multiplying through by mn simplifies the process. Ultimately, the solution for x is derived by isolating it on one side of the equation.
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Homework Statement


Hello I have this problem here:x/m - 1/n = 3x/mn. Solve for x.

Homework Equations


The Attempt at a Solution



I got it to this level:

xn = 3x + m

and the final answer is m / n - 3.

How do I go about getting the final answer? I just want to know what I'm missing because I don't see how to reduce it to the final answer. I always have these problems with fractions and division.
 
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What you want to do is to be able to factor out x. In such questions, we usually seek to reduce the equation to a form ax = b, where a and b are independent of x.
To do that, we clearly need all the terms containing x on one side to be able to factor it out. Please carry on :)
 
\frac{x}{m}\,-\,\frac{1}{n}\,=\,\frac{3x}{mn}

When someone says to multiply through by mn, what mathematics rule is that and how do you go about doing it?

Supposedly, multiplying through my mn gives:

xn\,-\,m\,=\,3x

but I don't see how.
 
Rewrite your equation as:
xn - 3x = m
x (n-3) = m
Do you see it now? The key idea is to bring all the 'x' terms on one side so you can factor it out.
 
I get these parts:

<br /> xn\,-\,m\,=\,3x<br />

<br /> x (n-3) = m<br />

But how do you get it from here to here:

<br /> \frac{x}{m}\,-\,\frac{1}{n}\,=\,\frac{3x}{mn}<br />

to here:

<br /> xn\,-\,m\,=\,3x<br />
 
Ok the issue is that I'm thinking about it like this:

if you subtract two fractions then you have to find the LCM or some common denominator. How do you do that with this or am I thinking about it wrong?

mn * x/m - mn * 1/n

What do you do with this? ;o
 
Amaz1ng said:
Ok the issue is that I'm thinking about it like this:

if you subtract two fractions then you have to find the LCM or some common denominator. How do you do that with this or am I thinking about it wrong?

mn * x/m - mn * 1/n

What do you do with this? ;o

The first term is m times n, times x, divided by m. m divided by m is 1, so it reduces to nx for the same reason that 2*3/2 = 3.
 
Ok I think I got it...I was thinking about it like a fraction.

Thanks alot. :D
 
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