Finding the square with a fraction in the expression

AI Thread Summary
The discussion revolves around rewriting the expression x^2 + x + 1/4 as the square of a binomial. Participants clarify that using the perfect square trinomial pattern, the expression can indeed be expressed as (x + 1/2)^2. There is a debate about whether a specific value 'a' can be found, with consensus emerging that a equals 1/2. The technique of completing the square is emphasized as a method to achieve this transformation. Ultimately, the expression is confirmed to be a perfect square.
Amaz1ng
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Homework Statement



x^2 + x + \frac{1}{4}

Homework Equations



This should be written in the form:

(x+y)^2

Just to add a bit more info, the exercise is to "Write each of the following as the square of a binomial expression". So basically the book teachs to take the rook of x^2 and 1/2, multiply those together, then multiply by 2. If that is equal to the middle term, then you can write:

(\sqrt{x^2} + \sqrt{1/4})^2

The Attempt at a Solution



My answer is that this can't be written as a square...which is what the textbook is asking to do. Anyway, I don't think this can be written as a square
 
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Hi Amaz1ng.

You are asked to find if there is a value a so you can write

x^{2}+x+1/4=(x+a)^{2}
 
If I have a number a, and I know a^2 = 1/4, what is a?
 
Karlx said:
Hi Amaz1ng.

You are asked to find if there is a value a so you can write

x^{2}+x+1/4=(x+a)^{2}
I don't believe there is such a value of a. You can, however write x2 + x + 1/4 as (x + a)2 + b.

This technique is called completing the square. Your textbook should have numerous examples of how to do this.
 
Just to add a bit more info, the exercise is to "Write each of the following as the square of a binomial expression".
 
Karlx said:
Hi Amaz1ng.

You are asked to find if there is a value a so you can write

x^{2}+x+1/4=(x+a)^{2}

Mark44 said:
I don't believe there is such a value of a.

Yes there is.

Using the perfect square trinomial pattern
a^2 + 2ab + b^2 = (a + b)^2
equate
x^{2} + x + \frac{1}{4}
with the left side to find a and b. If x corresponds to a, what corresponds to b?
 
answer in book.. :wink:

(x+\frac{1}{2})^2

..it's squared but for some reason the square doesn't show.
 
Well, has anyone checked to see if (x+1/2) * (x+1/2) = x^2+x+1/4?
Note: this would imply that a = 1/2 from Post #3 above.
 
eumyang said:
Yes there is.
I don't know why I didn't see that.:blushing:
eumyang said:
Using the perfect square trinomial pattern
a^2 + 2ab + b^2 = (a + b)^2
equate
x^{2} + x + \frac{1}{4}
with the left side to find a and b. If x corresponds to a, what corresponds to b?
 
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