Finding The Tension force with different angles

AI Thread Summary
The discussion revolves around calculating the tension forces (T1 and T2) in a system where a 20 lb mass is suspended by two strings at angles of 30 and 65 degrees. The user has established equilibrium equations for both the x and y directions but struggles with the algebra to isolate T1 and T2. They are advised to rewrite their equations to simplify the substitution process, leading to a clearer relationship between T1 and T2. The conversation highlights the importance of correctly incorporating all forces, including the weight of the mass, in the equations. Ultimately, the user is guided to substitute values to find the tensions accurately.
Ashleyz
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Homework Statement


I have done all the physics for this problem which I'll detail below. I am only having trouble in doing the simple math to single out the t1 or t2.

A mass is hanging from a ceiling. It is supported by two strings which both are attached above to the ceiling. String 1 is at an angle of 30. String 2 is at an angle of 65. While the
mass is 20 lb. ( in the center)





Homework Equations

Ma = 0 in both the x and y directions.



The Attempt at a Solution


left T (T1) =30 degrees

right T (T2) = 65 degrees.

ok, here are my equations that I get to:

X: T2cos(65) - T1cos(30) = 0

Y: T2sin(65) + T1sin(30) = 0

now I just need to solve for, say, T1 in the x dierection and use that new eq. to
pluge into Y. Right?
 
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The 20 pounds is the value of the weight of the hanging mass; it is not the mass. In your last equation in the y direction, you are missing a force.
 
right. I am missing -w. Sorry about the mistake.

Now what of the T that I need to solve for. I have Solved for the T in my
x and y equation and get bad nasty answers.
 
First plug in the value for cos 65, sin 65, etc. Then solve the 2 equations with the 2 unknowns as you see fit.
 
Do you mean this:

I'll take the x eq. and solve for t1.

I get T1 = T2cos(65) / cos (30)

now I can take this eq. for T1 and plug it in for T1 in the y eq?
 
It will be a lot easier if you rewrite your first equation as T1= T2(.423)/.866 = 0.49T2. Rewrite the 2nd equation in the same manner, then do the substitution.
 
PhanthomJay said:
It will be a lot easier if you rewrite your first equation as T1= T2(.423)/.866 = 0.49T2. Rewrite the 2nd equation in the same manner, then do the substitution.

I see.

T1 = T2(.49)

T2 = 21.74lb + T1(.54) I divided .92 into lbs., think you can do that.

now ill put T2 in the T1 eq. Right?
 
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