Finding the Torque in a 3000 lb Car Acceleration

AI Thread Summary
To find the torque needed for a 3000 lb car accelerating from 0 to 60 mph in 10 seconds, the calculation involves determining the force and the radius of the wheels. The acceleration is calculated as 6 feet/sec², leading to a mass of approximately 93.75 slugs. The force acting on the car is then calculated to be 562.5 lbs. The correct torque value needed is 825 ft-lbs, which is derived from the relationship between force, radius, and acceleration. Understanding the conversion of speed from mph to feet per second is crucial in these calculations.
Supernerd2004
Messages
20
Reaction score
0
I just need a little help going about solving this problem. This is first problem in this lesson, and it is driving me crazy. Any help would be great!

A 3000 lb car is accelerated from 0 to 60mph in 10 seconds. Find the torque needed if the car has wheels of 1 ft. Ans (825 ft lbs)

We know that T (torque) = Force X radius X sin (theta), but it doesn't seem that the equation is helpful in this problem.
Thanks,

Dan
 
Physics news on Phys.org
The force that accelarated the car also made the wheels turn, and this force is in the "horizontal" direction.
 
I guess I'm still a little confused. If the car went from 0 to 60 in 10 seconds, then the acceleration must be 6 feet/sec^2. So if the mass of the car is 3000/32 or 93.75 the force acting on the car is m X a = 562.5 lbs. This is where I get stuck. Thanks again for the quick response!

Dan
 
60 mph is approximately 88 ftps.
 
Wow, I can't believe I missed that. Thanks again so much for the help and the quick replies.

Dan
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Forces when car wheels "lay rubber"
Replies
5
Views
2K
Determine if a car can pop a wheelie?
Replies
15
Views
3K
Solving acceleration of a car with torques
Replies
12
Views
2K
Accelerating a car including the moment of inertia of the wheels
Replies
33
Views
11K
Start-up acceleration, max speed and torque of a transfer car
Replies
9
Views
3K
Ball rolls without slipping in an accelerating car
Replies
6
Views
3K
Where can I find the following coefficients for a car?
Replies
1
Views
1K
Finding Acceleration of a Car Where Crumpling Occurs (Momentum)
Replies
9
Views
2K
Force exerted on counter-rotating wheels by a tennis ball
Replies
44
Views
6K
A car traveling upward on inclined plane
Replies
11
Views
4K

Hot Threads

Recent Insights

Back
Top