Finding Thevenin Voltage in a Complex Circuit

AI Thread Summary
The discussion focuses on finding the Thevenin voltage in a complex circuit involving resistors. The user has calculated the equivalent resistance of series and parallel combinations but is confused about current division between resistors. It is clarified that since terminals A and B are open, they do not affect current flow, allowing for equal current division in parallel branches. The conversation emphasizes understanding that current flows through available paths, confirming that both branches have the same resistance. This understanding aids in determining the Thevenin voltage accurately.
sugz
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Homework Statement


The question is in the photo attached.

Homework Equations

The Attempt at a Solution


I have found the Thevenin voltage as the 10 and 20 ohm resistors are in series (30 ohms) and the 50 and 40 ohm resistor are in series (90ohms). The 30 and 90 ohm resistors are in parallel so

30||90 = (30×90)/(30+90) =22.5 ohms

I am having struggles with determine the Thevenin voltage as the solution says the 8 A current gets divided equally among the 10 and 20 ohm resistor but I don't understand why.
 

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What is the total resistance of each branch (ignore the terminals A and B for the moment)?
 
60 ohms but how can we ignore terminals a and b?
 
sugz said:
60 ohms but how can we ignore terminals a and b?
I said ignore them for the moment. You can do this because they are open: not connected to anything so they do not pass any current.

So both of these branches have the same resistance, correct? The branches are in parallel, correct? How will current divide between equal resistances in parallel?
 
So since current doesn't pass through terminal a and b, they just flow down to the next resistor?
 
sugz said:
So since current doesn't pass through terminal a and b, they just flow down to the next resistor?
Yes. They are the only available paths.
 
Okay, that makes sense then, thank you!
 
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