Finding thickness of a cast iron cylinder

AI Thread Summary
To determine the thickness of a cast iron cylinder with a 300mm bore under a pressure of 30 N/mm² and a working stress of 25 N/mm², the formula used is t = pd/2σ. The initial calculation yielded a thickness of 180mm, which was deemed too large. An edit suggested a recalculation leading to a thickness of 0.0014mm, but this was also questioned. The correct interpretation of pressure as 30 MPa was highlighted, indicating that the first calculation was likely accurate.
joe465
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Homework Statement



A cast-iron cylinder of 300mm bore carries a pressure of 30 Newtons per square
millimetre; what should be its thickness for a unit working stress of 25 Newtons per
square millimetre?

Homework Equations



ó1 = pd/2t

t=pd/2tó1

The Attempt at a Solution



t=pd/2tó1

t= 30*300/2*25

=180mm

Its got to be wrong as its way too big but I am unsure on where I am going wrong, any help would be much appreciated.

'Edit'

ó1/pd=2t

25/(30*3000) = 2t

2t = 0.00277778

t= 0.0014mm (4dp)

Maybes this one, I am not sure.

Thanks, Joe
 
Last edited:
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Your first one should be correct. Considering that the pressure is 30 MPa.
 

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