Finding time and initial velocity of a vertically displaced launch

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SUMMARY

The discussion focuses on calculating the time and initial velocity of a projectile launched from a height of 0.635 meters at an angle of 72.2°, landing 1.64 meters away. Participants emphasize the importance of using standard motion equations to solve the problem effectively. A suggestion is made to create a sketch of the projectile's trajectory to visualize the problem better. The need for sharing attempted solutions is highlighted to facilitate more targeted assistance.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with standard motion equations
  • Basic trigonometry for angle calculations
  • Ability to sketch and interpret projectile trajectories
NEXT STEPS
  • Review standard motion equations for projectile motion
  • Learn how to derive initial velocity from launch angle and distance
  • Practice solving projectile motion problems with varying heights and angles
  • Explore graphical methods for visualizing projectile trajectories
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone looking to improve their problem-solving skills in kinematics.

Brooke96
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Homework Statement


A projectile is launched 0.635 m above the ground at an angle of 72.2°. It lands on the ground 1.64 m away


Homework Equations





The Attempt at a Solution



Ive tried so many different equations and have looked up different ways, but I just don't know what I'm doing anymore
 
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We don't know what you've tried either. If you post your work, it would help us to see where you've gone wrong.

In any event, draw a sketch of your problem and use the standard motion equations.
 

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