Finding Time in an Oscillation Problem

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To solve the oscillation problem, the period of the first mass-spring system is given as 3.0 seconds. The second system has a mass six times heavier and a spring three times stiffer, which affects its oscillation period. The angular frequency for the second system can be calculated using the formula w = sqrt(ks/m), leading to a new period T. Given the different gravitational acceleration on the new planet, the calculations will yield the time for one complete oscillation. The final result will provide the duration for the second mass to complete its round trip.
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Homework Statement



Here on Earth you hang a mass from a vertical spring and start it oscillating with amplitude 2.4 cm. You observe that it takes 3.0 s to make one round trip.

You construct another vertical oscillator with a mass 6 times as heavy and a spring 3 times as stiff. You take it to a planet where gplanet = 8.0 N/kg. You start it oscillating with amplitude 3.9 cm. How long does it take for the mass to make one round trip?

Homework Equations



x = Acos(wt)

w= sqrt(ks/m) = 2pi/T

T= 2pi/w

f = 1/T = w/2pi
 
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