Calculating Time and Velocity in a Projectile Motion Problem

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The discussion centers on solving a projectile motion problem involving a car launching off a ramp at a 10-degree angle, landing 20 meters away with a vertical displacement of -1.5 meters. The user is trying to determine the time of flight (T) and is unsure how to calculate the horizontal velocity (Vx) and vertical velocity (Vy). They recognize the need to use the provided equations and to substitute one into another to eliminate the initial velocity (Vo) and isolate time. A key insight shared is that time can be expressed as T = 20.33/V, which is then used in the horizontal motion equation. The conversation emphasizes the importance of correctly applying the kinematic equations to find the solution.
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3rd week in AP physics... can't figure this out :'(

Homework Statement


delta X = 20m
delta Y = -1.5m
angle = 10 degrees

basically, a car goes off a 10 degree ramp and lands 20 meters away and the delta Y is 1.5m... my assumption is that I need to find T first.


Homework Equations


we are given 4 equations:
delta X = VxoT
Vy = Vyo + AyT
delta Y = VyoT + (1/2)AyT^2
Vy^2 = Vyo^2 + 2Ay(delta Ymax)



The Attempt at a Solution


i have no attempt.
 
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y=y0+vxt-1/2gt2

you want to find t when y=0 (y0=1.5)
 
rock.freak667 said:
y=y0+vxt-1/2gt2

you want to find t when y=0 (y0=1.5)


I don't know what Vx is.
 
Rubix said:
I don't know what Vx is.

the angle θ=10

so vx=vcosθ

and vy=vsinθ


Also I made a typo,the equation should be


y=y_0 +v_y t -\frac{1}{2}gt^2


(not vx in it)
 
A hint: You must plug one equation into another on this one, this will result in the removal of Vo from an equation and leaving only time.
 
I still need help, I know i need to plug in equations into each other but I'm not sure which ones
 
figured it out, the key was

t = (20.33/v)

then i plugged that into this eqn:

delta X = VxoT
 
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