Finding total charge from volume charge density

AI Thread Summary
To find the total charge from a volume charge density, integration is necessary because the charge density varies with distance from the center of the sphere. The given volume charge density is ρ=ρnaught*r/a, which means it increases linearly with r. Simply multiplying the total volume by the average charge density would not account for this variation, leading to incorrect results. The integration process effectively sums the contributions of infinitesimally small charge elements throughout the volume. Understanding this concept clarifies why integration is essential in this scenario.
emr564
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Why do I have to integrate? Isn't it redundant?

Homework Statement


The volume charge density inside a solid sphere of radius a is given by ρ=ρnaught*r/a, where ρnaught is a constant. Find the total charge as a function of distance r from the center.


Homework Equations


Q=ρV


The Attempt at a Solution


Q=(ρnaught*r/a)*(4/3)(∏a^3)
Q=(4/3)∏ρnaught*r*a^2

but the solution manual says it's supposed to be Q=∏ρnaught*a^3
It says that you have to integrate ρ with respect to V, and that's what confuses me. If you integrate, you're taking the charge of one tiny sphere and adding it the the charge of a concentric sphere a little bigger, so on and so forth, so doesn't that mean that each time you move up to a bigger sphere, you're being redundant? Why can't you multiply the total volume by the charge per volume to get charge?
 
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The charge density is zero at the center and gets larger with increasing r, as you wrote,

ρ=ρnaught*r/a
 
Thank you! I finally noticed that after way too long...
 
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