Finding total flux on Gaussian surface

AI Thread Summary
To find the total electric flux through a Gaussian surface inside a uniformly charged sphere, the total charge Q within the radius r must be considered, as r is less than R. The electric flux is calculated using Gauss's Law, which states that the flux is equal to the enclosed charge divided by the permittivity of free space (ε₀). Since the Gaussian surface is within the sphere, not all of Q contributes to the flux. The assumption is made that the sphere is a non-conductor, which affects the charge distribution. Understanding these concepts is crucial for correctly applying Gauss's Law in this scenario.
phymateng
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Homework Statement


Consider the uniformly charged sphere with radius R. Q is the total charge inside the sphere. Find the total flux passing through the Gaussian surface (spherical shell) with radius r. (r<R)

Homework Equations



I I tried solving for the Electric Flux by simply dividing the Q by Empselon Knot thought this was too simple to be right, and as I suspected it, it was wrong.

The Attempt at a Solution



I used the formula for the electric flux but using Q divided by Empselon Knot and got it wrong. Maybe I'm not getting the concepts right.
 
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Welcome to PF!

Hi phymateng! Welcome to PF! :smile:

(it's called "espilon nought" … oh, and have an epsilon: ε :wink:)

r < R, so the surface is inside the sphere, so it's not all of Q. :smile:
 
Thank you. Yes, Q is the total charge inside the sphere and they are asking me to find the total flux passing through a gaussian surface of radius r inside the sphere. Radius of sphere is R. (so r<R)
 
this solid sphere is a non conductor i assume..right?
 
it doesn't say. So I assume it isn't.
 
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