Finding Total Width of Ellipse in Standard Form

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How do you find the total width of the ellipse given by the equation 7x^2 + 7(y-6)^2 = 6?
 
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The "standard form" for an ellipse is
\frac{(x- x_0)^2}{a^2}+ \frac{(y- y_0)^2}{b^2}= 1
Where (x_0,y_0) is the center of the ellipse, a is the distance from the center of the ellipse and points where the ellipse crosses the x-axis and b is the distance from the center of the ellipse to the points where the ellipse crosses the y- axis. First change your equation to that form (Notice the "1" on the right hand side. How do you get that?). What does that tell you about the total width of the ellipse?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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