The discussion focuses on calculating the time it takes for a projectile, launched at 50 m/sec at a 53-degree angle, to reach a velocity that makes a 33.7-degree angle with the horizontal. The solution involves breaking down the motion into x and y components, utilizing the equations of motion. The final calculated time is approximately 2.03 seconds, confirmed by multiple participants using gravitational acceleration of 9.8 m/s².
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Yep, that worked! I've got 2 seconds as the answer and hopefully it must be correct. Thanks :-)Adrian Jimenez said:Take into consideration that the motion consists of both x and y components (x=vcosθ and y=vsinθ). Perhaps you could try calculating what the initial speed and final speeds are for the y component. Then try calculating how much time it would take for that change in speed using your other kinematics formulas.
I confirm 2 sec. (More precisely, 2.03, using 9.8 for g.)dahano said:Yep, that worked! I've got 2 seconds as the answer and hopefully it must be correct. Thanks :-)