Finding Velocity with Kinetic Energy.

AI Thread Summary
To find the velocity of a toy rocket at 165 meters using energy conservation, the work done by the thrust must equal the kinetic energy at that height. The thrust force of 30 N acting over the distance of 165 m results in 4950 J of work. This work must account for gravitational potential energy, calculated as Eg = mgh. By applying the conservation of energy principle, the kinetic energy at 165 m can be determined, allowing for the calculation of the rocket's velocity. The final velocity can be derived from the equation Ek = mv^2 / 2, factoring in the work done and gravitational effects.
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Homework Statement



I have to use energy conservation to solve this. So i cannot solve with kinematics

"On a windless day, the engine of a 250 g toy rocket exerts 30N of thrust straight upward until it burns out at a height of 165 m"

How fast is the rocket moving at 165m?

Homework Equations



Ek=mv^2 / 2
Em=eg+ek
Eg=mgh


The Attempt at a Solution



First i found my acceleration.

A= f/m
A= (30- 9.8 x .25) / 0.25
=110.2

Then subbed into

Vf^2 = 0 + 2(110.2)x165
190.1

But my teacher told us to use the law of conservation...
 
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Well the work done in moving the rocket 165 m will be equal to the kinetic energy of the rocket at 165 m.

How would you find the work done by the force of 30 N in moving 165 m?
 
rock.freak667 said:
Well the work done in moving the rocket 165 m will be equal to the kinetic energy of the rocket at 165 m.

How would you find the work done by the force of 30 N in moving 165 m?

Mutliply 30 by 165 which is 4950

oh... Then solve for v
 
You need to take into account gravity.
 
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