Finding voltage phasor resistance * current phasor

AI Thread Summary
To find the phasor voltage using the given current phasor I=75<120 degrees and resistance R=4k, only the magnitude of the current is multiplied by the resistance. The resulting voltage phasor is calculated as V=IR, which gives V=300000<120 degrees. The angle of the current phasor remains unchanged during this multiplication. Therefore, the correct approach is to multiply the magnitude of the current by the resistance while keeping the angle constant.
pokie_panda
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Homework Statement



I=75<120 deg.
R= 4k
find phasor voltage

does the 4,000 multiply the 75 only so you get

300000<120

or does it multiply 4,000 both values including the angle ?
 
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pokie_panda said:

Homework Statement



I=75<120 deg.
R= 4k
find phasor voltage

does the 4,000 multiply the 75 only so you get

300000<120

or does it multiply 4,000 both values including the angle ?

Multiplying a complex number or phasor by a real constant changes only its magnitude. The angle remains the same.
 
Thanks
 
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