First Law of Thermodynamics - easy q's

AI Thread Summary
The discussion addresses two homework problems related to the First Law of Thermodynamics. In the first problem, the user struggles with calculating the internal energy of a gas after adiabatic compression, mistakenly not converting units properly and failing to use consistent pressure units. The second problem involves calculating work done by a gas expanding under a specific pressure-volume relationship, where the user incorrectly applies the formula without considering the need for calculus due to the changing pressure. Participants emphasize the importance of unit conversion and consistency in calculations. Overall, the thread highlights common pitfalls in thermodynamic problem-solving and the necessity of understanding underlying principles.
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Homework Statement



The internal energy of a gas is 600 J. The gas is compressed adiabatically, and its volume decreases by 400 cm3. If the pressure applied on the gas during compression is 4 atm, what is the internal energy of the gas after the adiabatic compression?

Homework Equations


Change Q = Change U + Change W

The Attempt at a Solution



Since it's adiabatic then change in Q = 0...

So it should be change U = - change W...
(Ufinal - Uinitial) = - (4*4) ----I also tried changing atm to pascals, but the answer is still wrong.

What am i doing wrong? Anyone please.

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Homework Statement



A gas has an initial volume of 7.05 m3. It is expanded to six times its original volume through a process for which P = αV3, with α = 4.00 N/m11. How much work is done by the expanding gas?

Homework Equations



W = P*delta V

The Attempt at a Solution



So P = 4*7.05^3 = 28.2

delta V = (Vfinal - Vinitial) = (7.05*6) - 7.05 = 35.25 m3

so W = 994.05 J. The correct answer is 3.20e6 J, but I don't understand what I'm doing wrong. Anyone please?
 
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hello,

in the first problem you are not converting cm^3 to m^3 correctly. and you do need to use Pa for pressure. you must be consistent with your units throughout any formula.

if i understand the second problem correctly, the volume and pressure are changing at the same time and are related by P = a*V^3 (i assume the 3 is an exponent). for this, one needs calculus.

W = \int_{V_1}^{V_2}{P}dV
 
Woah. Thank you so much. I guess I was just too hungry to think right =/.
 
cheers.
 
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