Fixed end moments with a beam with udl

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The discussion centers on determining the end moments for a fixed beam subjected to a uniformly distributed load (UDL). It questions why the end moments are calculated as WL^2/12 instead of WL^2/4, highlighting the unique boundary conditions of fixed beams where both slope and deflection at the ends are zero. The conversation emphasizes the differences between fixed and simply supported beams, noting that simply supported beams typically have zero moments unless influenced by an applied couple. A request for a stepwise solution or reference to a detailed explanation is also made, referencing a Schaum's Outline for context. Understanding these mechanics is crucial for accurate structural analysis.
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I came across a reference where there is a beam (lets say length L)
both ends fixed... with a UDL of say "W" per unit length... i want to know how the end moments are W L^2/12 ...shudnt they be W L^2/4??


Its pretty simple mechanics. but it got me wondering,,,,
 
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In the fixed end beam, both the slope and deflection at the ends must equal zero. In a simply supported beam, there are different end conditions and the moments are typically zero, unless there is also an applied couple.
 
nice,,,
i wondered if u cud provide a solution or a link to the actual stepwise solving of one...
 
Here is an excerpt from a Schaum's Outline of Strength of Materials (prob. 11.6):

This problem shows a beam which is partially loaded with a UDL. The technique can be used when the UDL is extended the full length of the beam.
 

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