Fluid Mechanics: 2 Conceptual Doubts Answered

AI Thread Summary
The discussion revolves around two conceptual doubts related to fluid mechanics, with the second query being the primary focus. Participants express frustration over a lack of clarity regarding the doubts, as only a drawing of the problem has been provided without accompanying explanations. There is a request for others to share their thoughts and insights on the issues presented. The importance of showing work and reasoning in problem-solving is emphasized. Clear communication and detailed explanations are essential for effective assistance in understanding fluid mechanics concepts.
iitjee10
Messages
56
Reaction score
0
I had two conceptual doubts which are asked in the question.

It would be good if anyone can answer the first one but my main query is the second one
 

Attachments

  • Picture.jpg
    Picture.jpg
    20.1 KB · Views: 433
Physics news on Phys.org
iitjee10 said:
I had two conceptual doubts which are asked in the question.

It would be good if anyone can answer the first one but my main query is the second one

You need to show your work and thoughts.

CS
 
Have you seen my doubts? I rather think you havent.

Sorry if I sound rude
 
iitjee10 said:
Have you seen my doubts? I rather think you havent.

Sorry if I sound rude

I don't know what your doubts are. All you have attached is a drawing of the problem.

What are your thoughts on it and where is your work?

CS
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top