- #1

steem84

- 13

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Hello,

I have the following problem with respect to fluid mechanics:

A source of strength

With the velocity in the x-direction determined to be

To calculate the surface

I know this is the correct way to calculate the separation surface, but from this point I can not go further: how do I solve the integral? Or can I use some trick?

Btw: sorry for the clumsy format, but I can’t LateX

Thanks!

Steven

If this is the wrong sub-forum, please let me know

I have the following problem with respect to fluid mechanics:

A source of strength

*Q*is in a 3D space and subjected to a parallel flow*U*along the x-axis. The position of the source is at (xq,yq,zq). This will lead to the following velocity potential in cartesian and cylindrical coordinates**figure 1**With the velocity in the x-direction determined to be

**figure 2**To calculate the surface

**rho(x)**which separates the fluid (coming from the source) from the fluid, (coming from the parallel flow), one can use the law of volume conservation (because of constant density). In that body which is described by that surface, the flow through any plane x=constant should equal to**Q****figure 3**I know this is the correct way to calculate the separation surface, but from this point I can not go further: how do I solve the integral? Or can I use some trick?

Btw: sorry for the clumsy format, but I can’t LateX

Thanks!

Steven

If this is the wrong sub-forum, please let me know