Fluid Mechanics. Volume of a bubble.

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SUMMARY

The discussion centers on calculating the volume of a bubble released by a diver at a depth of 50 meters, where the water density is 1.02 g/cm³. The initial volume of the bubble is 1 cm³, and the pressure at that depth is 6 atmospheres. Using the ideal gas law, specifically the equation P1V1 = P2V2, the final volume of the bubble when it reaches the surface is determined to be 6 cm³.

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I was doing some online physics tests with my friend because we were bored and we both got stuck on this question, I was wondering if anyone might be able to help.

A diver at 50metres under the sea (1.02 density) releases bubbles 1cm^3 in volume. What will the volume be when the bubbles reach the surface?

(no temperature mentioned in the question)

Any help appreciated,
Many thanks.
 
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Wouldn't this just be a simple case of P1V1 = P2V2, where 1 = the initial conditions, i.e. a volume of 1 and pressure of 6 atmospheres (one atmosphere for every ten metres of depth and an obvious additional atmosphere so we're working with the total pressure), and P2 = 1. Therefore I get V2 = 6.
 

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