I don't have a diagram for this, so I'm going to do my best to describe it. A glass tube lying horizontally has three different cross-sectional areas, A, B and C. Area A is 12 cm^2, B is 5.6 cm^2, and C is 6.0 cm^2. Mercury (density = 13,600 kg/m^3) is being pushed through the tube by a piston open to the atmosphere at the end of area A. The mercury flows through area B and leaves the tube at area C with a velocity of 8.0 m/s. a) What is the total pressure at point A in area A? b) What is the total pressure at point B in area B? Relevant equations: Pressure = Force/Area Density = mass/volume A(1)v(1) = A(2)v(2) P(1) + (1/2)pv(1)^2 = P(2) + (1/2)pv(2)^2 } part of Bernoulli's equation ^all that comes to mind My attempt at a solution: To calculate the velocity of mercury through area A: A(1)v(1) = A(2)v(2) .12 m^2 * v(1) = .06 m^2 * 8 m/s v(1) = 4 m/s To calculate the velocity of mercury through area B: A(1)v(1) = A(2)v(2) .12 m^2 * 4 m/s = .056 m^2 * v(2) v(2) = 8.57 m/s I think that the total pressure at point A is just atmospheric pressure (1.013 * 10^5 Pa), but I'm not sure. When I use this value in Bernoulli's equation to calculate the pressure in area B, I get a negative number, which makes me think that my assumption is wrong.