Flux calculation using Gauss’s Theorem

  1. qn1.jpg

    Qn: A uniform electric field of strength 300 N/C at an angle of
    30º with respect to the x-axis goes through a cube of sides
    5 cm. (a) Calculate the flux through each cube face:
    Front, Back, Left, Right, Top, and Bottom. (b) Calculate
    the net flux through the entire surface. (c) An electron is
    placed centered 10 cm from the left surface. What is the
    net flux through the entire surface? Explain your answer

    Applying Gauss’s law the net flux can be calculated.
    And for option (B), i guess the flux will be 0. But not sure. can anyone explain all the 3 options?
  2. jcsd
  3. mfb

    Staff: Mentor

    Option B?
    That is right, and Gauss gives you the reason (is there divergence of the field inside the cube?).

    (a) cannot be solved with Gauss alone, but the integrals are easy to do.
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