The following vector field is given: F = < x + y^3, y, z - y^3 >
Let T be the solid given in cylinder coordinates by: r [0,1], tetha [0, pi], z [0, 2]
Find the flux out of the curved part of the surface of T.
2. The attempt at a solution
The normal vector n is < x, y, 0 >
F*n is therefore 1 + xy^3
Then I need dS = sqrt(1 + zx2 + zy2) dx dy. Is this simply 1 dx dy?