Flux - simple integral computation

AI Thread Summary
The problem involves calculating the flux of a uniform electric field E = 4i through a surface with area vector A = 2i + 3j. The discussion highlights confusion about using the area vector A directly in the flux calculation, as the integral typically involves the differential area vector dA. However, since the electric field is uniform and the area is constant, the flux can be simplified to the dot product of E and A. The correct calculation yields a flux of 8 units, confirming that the approach of using the area vector directly is valid in this context. This problem illustrates the application of integral calculus in vector analysis for flux computation.
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Homework Statement


A surface has the area vector A = 2i + 3j. What is the flux of a uniform electric field through it if the field is E = 4i?

2. Homework Equations
Integral calculus, vectors

The Attempt at a Solution


I don't understand why one could do this. The integral is of E and dA, not E and A. How can I use A to determine dA?

This is a crackpot way I thought of

\Phi = \int \vec{E} \cdot \vec{dA}

<br /> \Phi = \vec{E} \cdot \int \vec{dA} <br />

<br /> \Phi = \vec{E} \cdot \vec{A} <br />

Then Phi = 4i dot (2i + 3j) = 8 flux units

This seems like wild fantasy though as I don't know if I can pull out a constant from a dot product integral
 
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There is no dA to speak of. You are given A which is the same everywhere and E which is uniform. Just take the dot product as you have in your third equation. There isn't much to this problem/
 
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