- #1
mahler1
- 222
- 0
I am given the parametrized curve ##\alpha:(-1,\infty) \to \mathbb R^2## as ##\alpha(t)=(\dfrac{3at}{1+t^3},\dfrac{3at^2}{1+t^3})##.
I am asked to show that the line ##x+y+a=0## is an asymptote. So, I have to prove that when ##t \to \infty##, the curve tends to that line. My doubt is: The limit of ##\alpha(t)## when ##t \to \infty## is ##(0,0)##, how is it possible that the curve tends to the origin and at the same time to that line? How could I show that the line is in fact an asymptote of the curve?
I am asked to show that the line ##x+y+a=0## is an asymptote. So, I have to prove that when ##t \to \infty##, the curve tends to that line. My doubt is: The limit of ##\alpha(t)## when ##t \to \infty## is ##(0,0)##, how is it possible that the curve tends to the origin and at the same time to that line? How could I show that the line is in fact an asymptote of the curve?