Force acting on a block against a wall

AI Thread Summary
A 1.0 kg wood block is pressed against a vertical wall with a 12N force at a 30-degree angle, raising the question of its potential movement. The coefficients of static and kinetic friction are given as 0.50 and 0.20, respectively. To determine if the block will move, a free body diagram (FBD) must include all acting forces, including gravity. Participants suggest ensuring all forces are accounted for and analyzing their effects on the block's movement. The discussion emphasizes the importance of correctly applying static and kinetic friction in the analysis.
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Homework Statement


A 1.0 kg wood block is pressed (30 degrees) against a vertical wood wall by a 12N force as in the picture. If the block is initially at rest, will it move upward, downward, or stay at rest? In the book, it gives the us as 0.50 and the uk as 0.20.
Untitled.jpg

Free Body Diagram:
Untitled1.jpg


Homework Equations





The Attempt at a Solution


How do I solve this problem using static and/or kinetic friction?
 
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If you put up your images on a hosting website (like flickr or photobucket, etc) it will be much easier since your attachments still haven't been approved and we won't be able to see them until they are.

Or you could just describe it?
 
http://s245.photobucket.com/albums/gg65/darlieally/?action=view&current=Untitled.jpg
It's supposed to say 30degrees

And then the free body diagram (which I am not quite sure that I have done properly):
http://s245.photobucket.com/albums/gg65/darlieally/?action=view&current=Untitled1.jpg

Can you see these?
 
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Or if you can't see those...
http://s245.photobucket.com/albums/gg65/darlieally/?action=view&current=Untitled1.jpg"

and

http://s245.photobucket.com/albums/gg65/darlieally/?action=view&current=Untitled.jpg"
 
Last edited by a moderator:
Have you included gravity in your FBD? Once you have all of your forces for the FBD, look at which way the box could possibly move. You have the values of all of the forces including coefficients of friction, so how do these come into play?
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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