Force and Energy Homework: Solving for Weight and Horizontal Force | Physics"

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The discussion revolves around solving a physics homework problem involving weight and horizontal force. The weight is calculated as 470.4 N using the formula w = mg, where m is mass and g is gravitational acceleration. The horizontal force is computed as 160.88 N using F_x = mg*cos(70), with an emphasis on including units and direction. Participants highlight the importance of noting both magnitude and direction in the final answer. The direction of the force is identified as being along the incline in the direction of displacement.
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Homework Statement



http://img505.imageshack.us/img505/5230/123ae2.png​
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2. The attempt at a solution

A)
w=mg
w=48kg*9.8N/kg
w=470.4N

B)
F_x = mg*cos(70)
=48kg*9.8N/kg*cos (70)
=160.88
Is that right​
​
​
 
Last edited by a moderator:
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help me......
 
Looks good to me, but don't forget the units, and you need to note the direction of the force as well as the magnitude.
 
B)
F_x = mg*cos(70)
=48kg*9.8N/kg*cos (70)
=160.88N(U)
Is that right
 
How can i ind magnitude direction?
 
raman911 said:
How can i ind magnitude direction?

I think it is along the incline in the direction of displacement.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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