Force and Motion Homework: Draw Free Body Diagram & Compare Fnorm to Fgrav

  • Thread starter Thread starter AnomalyCoder
  • Start date Start date
  • Tags Tags
    Force Motion
AI Thread Summary
The discussion centers on understanding free body diagrams and the relationship between normal force (Fnorm) and gravitational force (Fgrav) for a person in an upward-moving elevator. It clarifies that while Fgrav remains constant near Earth's surface, the scenario changes if the elevator accelerates upwards, necessitating an unbalanced force. Newton's 2nd Law indicates that if the elevator accelerates upwards, the net force must also be upwards, implying that Fnorm must be greater than Fgrav. The conversation emphasizes the importance of drawing a free body diagram to visualize the forces acting on the person and to apply the equation for net force. Understanding these concepts is crucial for solving problems related to force and motion in physics.
AnomalyCoder
Messages
29
Reaction score
0

Homework Statement


I'm quite confused with the material that has been presented to me in my physics class.
The scenario is:
There is a person that is riding an elevator that is traveling upwards.
Draw a free body diagram for the person.
(Is Fnorm larger than Fgrav?)


Homework Equations



Fnorm, Fgrav.

The Attempt at a Solution


Well I'm just generally confused. Can Fgrav change, since gravity technically stays the same, assuming we stay on Earth?
Some clarification would be great.
 
Physics news on Phys.org
AnomalyCoder said:
Well I'm just generally confused. Can Fgrav change, since gravity technically stays the same, assuming we stay on Earth?
Some clarification would be great.

Assuming that the elevator remains close to the Earth's surface, Fgrav doesn't change. It is equal to mg, and you can take g to be a constant.

The key to understanding this problem is to use Newton's 2nd Law. Unfortunately,
There is a person that is riding an elevator that is traveling upwards.
is too vague a statement. Did the problem mean that the person is accelerating upwards? If so, what does Newton's 2nd Law say about the net force on that person?

Now consider the two forces acting on the person that together comprise that net force. For there to be a net force, these two forces must obviously be unbalanced. The question is just, in what manner?
 
It's actually accelerating at 2m/s, upwards. The person weighs 80kg. What would be greater; Fgrav or Fss. And if I have one of the forces, fgrav or fss, how could I obtain the missing force?
 
AnomalyCoder said:
It's actually accelerating at 2m/s, upwards. The person weighs 80kg. What would be greater; Fgrav or Fss. And if I have one of the forces, fgrav or fss, how could I obtain the missing force?

What does Newton's 2nd Law say about the direction of the net force? It has to be upwards, since the body is accelerating upwards, right? (You can also get the magnitude, since you know the mass, and F = ma).

Now, if two forces are acting on this body, and their vector sum has to produce a net upward force, which of the two forces must be greater in magnitude? The one that points up or the one that points down?

That's how we reason our way to the answer. More systematically: draw a free body diagram for the object, and from this you have an inventory of all the forces acting on it. Then write down the equation you get from:

sum of all forces = net force = ma.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top