Force between Parallel Wires: Calculating Resultant Force

AI Thread Summary
To calculate the force per unit length on two parallel wires carrying currents of 30A and 20A, one must first determine the magnetic field each wire generates due to the other, using Ampère's Law. The magnetic force can then be calculated with the formula F = I * L * B, where I is the current, L is the length of the wire, and B is the magnetic field. The resultant force incorporates both the magnetic forces from the wires and the Earth's magnetic flux density, which is 2*10^-5. The key is to compute the magnetic fields accurately and consider their directions, as they can affect the overall force calculation. Ultimately, the expected answers for the forces per unit length are 0 and 1mN, indicating a need to clarify the interaction of the forces.
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1. The problem statement, all variables and given/known
Two long parallel vertical wires 0.3m apart are. ' placed east-west of one another. The current in the westerly wire is 30A and on the other 20A. The horizontal component of the Earth's magnetic flux density is 2*10^-5. Find the force per unit length on each wire. (The answers are 0 and 1mN but I don't know why)
I calculated the force on each wire due to the earth. Then I calculated the force due to the wires. Thesr 2 forces are perpendicular so I used pythagoras to find resultant but my answer was wrong

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The Attempt at a Solution

 
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May I suggest you first figure the magnetic field (or magnetic flux density) on each wire due to the other wire. The magnetic field can be obtained using Amps Law. From the magnetic field you can then obtain the magnetic force which in this case is given by F=I*L*B where I is current, L is the length of the wire and B is the magnetic field. You only need the Force per unit length or (F/L)=I*B, so all you really need to do is compute the magnetic fields on the wires and you should be good to go. Don't forget to add the magnetic force on both wires due to the Earth.
 
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