Force Calculation in High Jump Takeoff

  • Thread starter Thread starter pennywise1234
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
During a high jump takeoff, a jumper weighing 800N exerts a force of 3 kN against the ground. According to Newton's third law, the ground exerts an equal and opposite force back on the jumper. Therefore, the force exerted by the ground on the high jumper is also 3 kN. The initial calculations involving mass and acceleration are unnecessary for this problem. Understanding the application of Newton's laws is key to solving force-related questions in physics.
pennywise1234
Messages
44
Reaction score
0

Homework Statement


A high jumper with a body weight of 800N exerts a force of 3 kN against the ground during takeoff.
How much force is exerted by the ground on the high jumper?

Homework Equations


f=m x a
a=f/m

The Attempt at a Solution


I converted 800n into KN giving me 0.8

I then divided a=3kn/0.8kn

is this right?

if not, how do i fix the issue
 
Physics news on Phys.org
Hint: It's a trick question! (Consider Newton's 3rd law.)
 
  • Like
Likes pennywise1234
so 3kn, because every action has equal and opposite reaction. thank you
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top