- #1

bydesign

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**The Question**: A high diver of mass 68.4 kg jumps off a board 9.5 m above the water.

The acceleration of gravity is 9.8 m/s2 .

If his downward motion is stopped 5.92 s after he enters the water, what average upward

force did the water exert on him?

Answer in units of N.

## Homework Equations

:v = v0 + at (To determine acceleration

EF (Average Force) = ma

## The Attempt at a Solution

:Well, I first have to find the acceleration of the water on the swimmer :

v = v0 + at

0 = (9.5m*9.8m/s^2) + a (5.92)

-93.1 = a (5.92s)

-15.726 m/s^2 = a

Now I plug that into F = ma

F = ma = (68.4 kg) (-15.726 m/s^2) = -1075.682 N

This looks about right, but when I put it into Quest, it comes out wrong. I've checked my math over twice. What am I doing wrong?

Thanks for the help :)