Force necessary to support mass on Hydraulic Jack?

AI Thread Summary
To determine the force necessary to support a mass of 904 kg on a hydraulic jack, the discussion revolves around applying the equation F1*d1 = Fp*d2, where F1 is the force on the smaller piston and Fp is the force exerted by the hand. The user initially calculated Fp incorrectly as 242.98 N and later attempted to solve it again, arriving at 8858.92 N, which was also deemed incorrect. The key point is that the pressure must be equal across both pistons, leading to the relationship F1 A1 = F2 A2. Ultimately, the user resolved the issue with assistance from others in the forum.
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Force necessary to support mass on Hydraulic Jack?

Homework Statement


Piston 1 in the figure has a diameter of 1.31 cm. distance of 2 in
Piston 2 has a diameter of 7.91 cm. distance of 10 in
In the absence of friction, determine the force F, necessary to support an object with a mass of 904 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).

Homework Equations


F1*d1 = Fp*d2, where d1 is the moment arm of F1, and d2 is
the moment arm of Fp.

The Attempt at a Solution


Fp = (F1*d1)/d2
(904)(9.81)/(pi)(0.003955)^2= F/(pi)(0.00655)^2
F=242.98 N which was incorrect.
anyone have an idea of what I should do and what equation to use? Thanks!
 
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I think we'll need to see the figure before we can help you out.
 


http://img6.imageshack.us/img6/7849/1808317ca439856447261f7.gif

this is the link for the picture.
 
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Neglecting the height difference means the pressure should be the same, thus F_1 A_1 = F_2 A_2

This is would be the force exerted on the small piston.

You should know how to find the force needed by the hand from this.
 


jumpingjack90 said:

Homework Equations


F1*d1 = Fp*d2, where d1 is the moment arm of F1, and d2 is
the moment arm of Fp.

The Attempt at a Solution


Fp = (F1*d1)/d2
(904)(9.81)/(pi)(0.003955)^2= F/(pi)(0.00655)^2
F=242.98 N which was incorrect.
anyone have an idea of what I should do and what equation to use? Thanks!

You have correctly found F1, the force on the smaller piston. However, they are asking for Fp (labelled simply F in the figure), the force exerted by the hand.

You have the equation to find Fp given F1.
 


ok. I used the equation given and solved for Fp. I had (242.98)(pi*(0.03955)^2))/(pi)*(0.00655)^2=Fp=8858.92 N, which is also incorrect.
what am I doing wrong?
 


nvm. I solved it! thanks everyone for your input!
 


jumpingjack90 said:
nvm. I solved it! thanks everyone for your input!

how u solved it my friend?
 
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