Force of interaction between two halves of a cylinder of charge.

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SUMMARY

The force of interaction per unit length between the upper and bottom halves of a uniformly charged cylinder with charge density ρ is given by the formula ρ²R³/3ε₀. The discussion highlights the challenge of finding an analytic expression for the electric field of a half-cylinder, emphasizing that the problem assumes zero separation between the two halves. Participants suggest that the electric field can be approximated by the field inside an infinitely long cylinder, which simplifies the calculations.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with charge density concepts
  • Knowledge of the formula for electric field due to a cylinder
  • Basic calculus for gradient calculations
NEXT STEPS
  • Study the derivation of the electric field for an infinitely long charged cylinder
  • Learn about the concept of interaction energy in electrostatics
  • Explore advanced topics in electrostatics, such as the method of images
  • Investigate numerical methods for approximating electric fields of complex charge distributions
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Physics students, electrical engineers, and anyone studying electrostatics or working on problems involving charged cylindrical geometries.

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Homework Statement


Find the force of interaction per unit length between the upper and bottom halves of a cylinder of uniform charge density rho.


Homework Equations



Solution should be \rho^2R^3/3\epsilon_0


The Attempt at a Solution



Frustrated cause I've solved this problem in the past and don't recall how to do it.

There's no analytic expression for the field of half a cylinder yes? How would I start to set the problem up? Would I have to find the interaction energy first then take its gradient?
 
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There's no analytic expression for the field of half a cylinder yes? How would I start to set the problem up? Would I have to find the interaction energy first then take its gradient?

I think the problem is assuming that the separation between the two halves is 0. If not, it would have given you the separation, which it didn't. So the field is just the field inside an infinitely long cylinder.
 
ideasrule said:
I think the problem is assuming that the separation between the two halves is 0. If not, it would have given you the separation, which it didn't. So the field is just the field inside an infinitely long cylinder.

For the E field I just divided my expression for charge inside\rho.r^2/R^2 by the surface of a finite cylinder 2pi*rL. Doesn't get me anywhere near the answer.
 

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