Force of repulsion of alpha particle

adichy
Messages
29
Reaction score
0

Homework Statement



An alpha particle has a mass m = 6.64x10^-27 kg and a charge q = +2e.
Compare the force of electric repulsion between two alpha
particles and the force of gravitational attraction between them. Explain briefly
why the gravitational force is ever significant, given its seeming insignificance
here.

Homework Equations


F=qE, F=kqq/r, F=ma

The Attempt at a Solution


coloumbs law can't be applied here since I am not given r
and i can't think of a way to obtain the E_field or a in f=ma when i equate qE=ma
(maybe Electric flux can be found using gauss's, but i don't think that's the right way to go)

Some guidance would be much appreciated

thanks
 
Physics news on Phys.org
Both the magnitude of the electromagnetic force and that of the gravitational force depend on the distance between sources. Can you come up with a mathematical combination of the two that is independent of the distance?
 
im not sure how eliminate the distance

F_e=kqq/r
F_g=Gmm/r^2

equating those 2 will still leave me with distance
I can't think of any other formula for F_e that doesn't require finding the electric field or using the distance
 
First, go back to your text or notes and find the correct expression for the Coulomb force (what you have is the potential energy). Second, you don't really want to equate the EM and gravitational forces, but the correct expression should be clearer once you can compare the correct dependences on the separation.
 
oh sorry i forgot its squared...
ahh divide both the expressions to find the ratio?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top