Force of Vehicles Traveling at 13.4112m/s

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To calculate the force of two vehicles traveling at 13.4112 m/s, one weighing 65 kg and the other 75 kg, the equation F=ma is essential. The discussion highlights the importance of understanding kinetic energy and momentum, with the 65 kg vehicle having a kinetic energy of 5845.4593 kJ and the 75 kg vehicle 6744.7607 kJ. The crumple zone of 0.5 m is relevant for assessing the impact force, as it can absorb energy and reduce the force experienced during a collision. The user seeks guidance on calculating the change in energy upon impact, indicating a focus on the effects of the crumple zone and momentum change. Overall, the conversation revolves around applying physics principles to analyze vehicle collisions effectively.
fireblade101
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I am trying to figure out force of each vehicle if both traveling at 13.4112m/s one weighing 65kg and the other 75kg many thanks in return forgot to add they both have a crumple zone 0f .5m each
 
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What do you mean by crumple zone ( I know what it is but what do you want to do with it?) and F=ma is the equation you're looking for.
 
I do understand f=mxa The problem I have is I have worked out the kinetic energy of each vehicle and the momentum of each vehicle but if the vehicle is traveling at 13.4112 m/s how do I figure the acceleration so as to figure the force. also once the impact occurs would the crumple zone show a difference in force of impact rather then a straight impact. I am also trying to figure out the change in momentum if anyone can help I would much appreciate Struggled with this question all day many thanks
 
I have figured out the force of the vehicles and the change in momentum I now need to calulate the change in energy. the 65kg vehicle has a kenetic energy of 5845.4593kj and the 75kg vehicle has a kenetic energy of 6744.7607kj can anyone tell me what i should do to calculate the change of energy on impact many thanks
 

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