Force of water on a pulled barge with angle

AI Thread Summary
To determine the force exerted on the barge by the water, the net force must be calculated using Newton's second law (F=ma), where the mass of the barge is 9200 kg and its acceleration is 0.10 m/s². The horse pulls with a force of 7900 N at an angle of 18°, which requires resolving this force into its components. The force of the water acting on the barge is the unknown that balances the net force, factoring in both the horizontal and vertical components of the forces. The direction of the water's force can be found by analyzing the net forces acting on the barge. This approach leads to a comprehensive understanding of the dynamics affecting the barge's motion.
bravohimz
Messages
3
Reaction score
0

Homework Statement



Suppose that the horse pulls on the rope with a force of 7900 N at an angle of 18° to the direction of motion of the barge, which is headed straight along the canal. The mass of the barge is 9200 kg, and its acceleration is 0.10 m/s2. What are the magnitude and the direction of the force on the barge from the water?



(a) Magnitude


(b) Direction (counterclockwise from the +x axis is positive)


Homework Equations



f=ma
trigs


The Attempt at a Solution



I trigged it;

(mass of the barge x the acceleration)-force of the horse cos (angle) = nope
 

Attachments

  • 05_58.gif
    05_58.gif
    11.2 KB · Views: 548
Physics news on Phys.org
What forces act on the barge? (The force of the water will be your unknown.) What's the net force on the barge? Set the net force = ma. Consider components parallel and perpendicular to the direction of motion.
 
ohhhhhh
thank you so much !
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top