Force on an Incline Plane Problem HELP

AI Thread Summary
A 63-kg skier on a 30° incline with a friction coefficient of 0.20 is trying to calculate acceleration. The initial calculation yielded -102.14, but the correct approach involves using the equation mAnet = mgsin(30) - μFn, where Fn is derived from Fn = mgcos(30). The skier mistakenly thought to input the absolute value, leading to confusion when the answer was marked incorrect. Clarification was provided that mass cancels out in the equation, simplifying the calculation. The skier was guided to correctly substitute values to find the proper acceleration.
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Homework Statement


A 63-kg person on skis is going down a hill sloped at 30° from the horizontal. The coefficient of friction between the skis and the snow is 0.20. What would be the magnitude of the acceleration?

Homework Equations


f=ma
fg=mg
fnet=mAnet
Ff=μῦFn

The Attempt at a Solution


I got -102.14, but I'm supposed to put it in as 102.14 right? Because the magnitude is the absolute value of whatever I get..? I found Fnet by subtracting Ff from Fg,x. I got 535.23 for Fn.

PLEASE HELP!? I put in 102.14 on the Webassign but it came back as wrong.

Thank you all!
 
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Show your calculations.
 
Fn = Fg,y
Fn = mgcos30
Fn = 63(9.81)cos30
Fn = 535.23

Fnet = mgsin30 - μῦFn
mAnet = mgsin30 - μῦFn
Anet = gsin30 - μῦFn
Anet = 9.81sin30 - 0.2(535.23)
Anet = -102.14

And as I mentioned earlier, I changed it to positive 102.14.

Thanks for your time.
 
mAnet = mgsin30 - μῦFn

The above equation should be

m*Anet = m*g*sin(30) - μ*m*g*cos(30)

Now solve for A.
 
Thank you for your help, I didn't realize m canceled out for the Fn formula until you showed me how I could use substitution. Thank you!
 
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