Force on an Object: Find Force Exerted by 7.0kg Block

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To find the force exerted by the 7.0 kg block on the 9.0 kg block, first calculate the total mass of the system, which is 17.0 kg (1.0 kg + 7.0 kg + 9.0 kg). The acceleration of the system can be determined using Newton's second law, F = ma, resulting in an acceleration of approximately 1.18 m/s² when a 20 N force is applied. The force exerted by the 7.0 kg block on the 9.0 kg block can be calculated by multiplying its mass by the acceleration, yielding a force of about 8.25 N. Similarly, the force exerted by the 7.0 kg block on the 1.0 kg block is also 8.25 N, as both blocks accelerate together. Understanding the relationship between mass, acceleration, and force is crucial for solving these mechanics problems.
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Homework Statement



Blocks with masses of 1.0 kg, 7.0 kg, and 9.0 kg are lined up in a row on a frictionless table. All three are pushed forward by a 20 N force applied to the 1.0 kg block.

A) How much force does the 7.0 kg block exert on the 9.0 kg block?

B) How much force does the 7.0 kg block exert on the 1.0 kg block?I am unsure of where to start or an equation to even use. help on how to solve it would be greatly appreciated
 
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for most of the mechanics problems draw the FBD(labeling all forces) and put in equations obeying F=ma...and solve.

PS: try posting atleast your idea of the problem..
 
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