Force on Current-Carrying Conductor

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    Conductor Force
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Homework Help Overview

The discussion revolves around a problem involving a proton moving in a magnetic field, specifically focusing on determining the radius of its circular path. The subject area includes concepts from electromagnetism and circular motion.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to identify the appropriate equation to relate the magnetic force and the radius of the circular motion. Some participants suggest using the relationship between magnetic force and centripetal force to find the radius.

Discussion Status

Participants are engaging in clarifying the approach to the problem. Guidance has been offered regarding the use of the magnetic force equation and its relation to centripetal force, indicating a productive direction in the discussion.

Contextual Notes

The original poster expresses uncertainty about the equations relevant to the problem, indicating a potential gap in understanding the application of the concepts involved.

cocololo
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Homework Statement



A proton (q = 1.6 x 10-19C; m = 1.7 x 10-27 kg) is in a uniform 0.25 T magnetic field. The proton moves in a clockwise circle with a tangential speed of 2.8 x 105 m/s.

What is the radius of the circle?

Homework Equations



Not sure what equation to use.

The Attempt at a Solution



We had been learning about magnitude of a magnetic field, and the equation we were working with was B=Fmagnetic/qV, I wasn't sure how to use this to find radius.
 
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Hi cocololo. Yes you can use the equation F=Bqv, which is the force due to the magnetic field which always points towards the centre of the circle so you can equate the magnetic force to the centripetal force and you should be able to workout the radius from that.
 
Oh, of course! I think I was thinking way too hard about this looking for something way more complicated than it actually was. Thanks!
 
You're welcome. Anything else you need help with?
 

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