Force on Space Ship: Mag to Nearest MN

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The discussion focuses on calculating the gravitational force acting on a spaceship due to nearby asteroids, given specific distances. The relevant equations include Newton's law of universal gravitation, which states that force is inversely proportional to the square of the distance. The initial calculation suggests zero force, but this is challenged by the fact that the spaceship is closer to one asteroid, which should affect the gravitational force experienced. The key point is that gravitational force depends on position rather than the spaceship's velocity. Accurate calculations must consider the varying distances to each asteroid to determine the net force.
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Homework Statement


IF D = 1954 meters and d = -92 meters, to the nearest MN what is the magnitude of the force on the space ship
ship2.gif


Homework Equations


F=(Gmass) / r^2
F=(G x mass asteroid) / (D/2)^2

ΣFx= F asteroidright - F asteroidleft = ma

The Attempt at a Solution


F asteroid right = F asteroid right = 0N

However I don't think this right because the ship is moving towards the asteroid on the right
 
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You are ignoring the fact that the ship is closer to one of the asteroids than to the other? The gravitational force depends only on position and not on velocity.
 

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