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**1. Three blocks are in contact with each other on a frictionless horizontal surface.The masses of the blocks are m1 = 1 kg , m2 = 2 kg, m3 = 3 kg. A horizontal force F = 24 N is applied on m1.**

a. Find the net force on each block.

b. Find magnitude of the contact forces between the blocks.

a. Find the net force on each block.

b. Find magnitude of the contact forces between the blocks.

**2. Homework Equations**

F= ma

F= ma

**3. The Attempt at a Solution**

I found the net acceleration, that equals to Fnet/(m1+m2+m3)

and then for a) I just multiplied each mass by net acceleration to get the force. Like for mass 3, I multiplied net acceleration by mass 3

and then for b)

between the m1 and m2

Net force on m1 is force applied - force exerted on it by m2

and the force exerted by the forward masses equal to summ of m2+m1 divided by m1+m2+m3, and times total force<24 N>

..... <I get lost after this>

I found the net acceleration, that equals to Fnet/(m1+m2+m3)

and then for a) I just multiplied each mass by net acceleration to get the force. Like for mass 3, I multiplied net acceleration by mass 3

and then for b)

between the m1 and m2

Net force on m1 is force applied - force exerted on it by m2

and the force exerted by the forward masses equal to summ of m2+m1 divided by m1+m2+m3, and times total force<24 N>

..... <I get lost after this>

I am confused for both parts. Wondering if I am on right track?