1. Three blocks are in contact with each other on a frictionless horizontal surface.The masses of the blocks are m1 = 1 kg , m2 = 2 kg, m3 = 3 kg. A horizontal force F = 24 N is applied on m1. a. Find the net force on each block. b. Find magnitude of the contact forces between the blocks. 2. Relevant equations F= ma 3. The attempt at a solution I found the net acceleration, that equals to Fnet/(m1+m2+m3) and then for a) I just multiplied each mass by net acceleration to get the force. Like for mass 3, I multiplied net acceleration by mass 3 and then for b) between the m1 and m2 Net force on m1 is force applied - force exerted on it by m2 and the force exerted by the forward masses equal to summ of m2+m1 divided by m1+m2+m3, and times total force<24 N> ..... <I get lost after this> I am confused for both parts. Wondering if I am on right track?