- #1
harmeet_angel
- 26
- 0
1. Three blocks are in contact with each other on a frictionless horizontal surface.The masses of the blocks are m1 = 1 kg , m2 = 2 kg, m3 = 3 kg. A horizontal force F = 24 N is applied on m1.
a. Find the net force on each block.
b. Find magnitude of the contact forces between the blocks.
2. Homework Equations
F= ma
3. The Attempt at a Solution
I found the net acceleration, that equals to Fnet/(m1+m2+m3)
and then for a) I just multiplied each mass by net acceleration to get the force. Like for mass 3, I multiplied net acceleration by mass 3
and then for b)
between the m1 and m2
Net force on m1 is force applied - force exerted on it by m2
and the force exerted by the forward masses equal to summ of m2+m1 divided by m1+m2+m3, and times total force<24 N>
... <I get lost after this>
I am confused for both parts. Wondering if I am on right track?
a. Find the net force on each block.
b. Find magnitude of the contact forces between the blocks.
2. Homework Equations
F= ma
3. The Attempt at a Solution
I found the net acceleration, that equals to Fnet/(m1+m2+m3)
and then for a) I just multiplied each mass by net acceleration to get the force. Like for mass 3, I multiplied net acceleration by mass 3
and then for b)
between the m1 and m2
Net force on m1 is force applied - force exerted on it by m2
and the force exerted by the forward masses equal to summ of m2+m1 divided by m1+m2+m3, and times total force<24 N>
... <I get lost after this>
I am confused for both parts. Wondering if I am on right track?