Force required to immerse a wooden cube

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To completely immerse a wooden cube with a side of 4 cm and a relative density of 0.5 in water, the force required is calculated using the cube's density and volume. The cube's weight is determined to be 64 x 10^-6 x 500 x 9.8 N, while the upthrust is 64 x 10^-6 x 1000 x 9.8 N. The force required is found by subtracting the weight from the upthrust, resulting in a value of 32 x 10^-3 kgwt. This confirms that option 2 is indeed the correct answer. The calculations demonstrate the relationship between weight, upthrust, and the force needed for immersion.
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Homework Statement



The force required to immerse a wooden
cube of side 4 cm and relative density RD 0.5 completely in water is
1) 16x10-3 kgwt
2) 32x10-3 kgwt
3) 64x10-3 kgwt
4) 128x10-3 kgwt

Homework Equations

The Attempt at a Solution



Density of the cube = 0.5 gcm-3
Volume of cube = 64 cm3
Weight of the cube = 64 x10-6 x 500 x 9.8 N (1)

Upthrust = 64 x10-6 x 1000 x 9.8 N (2)

Force required = Upthrust - Weight

Subtracting (1) from (2)

Force required = 64 x10-6 x 500 x 9.8 N

1kgwt = 9.8 N

Force required = 32 x10-3 kgwt

Is option 2) the correct answer ?
 
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it looks good to me.
 
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