- #1
tom_backton
- 8
- 0
This is a question about classic mechanics.
Let's say there is a disk in mid-air. There are only 2 dimentions, which is why it's a disk and not a ball...anyway, force is applied to the disk, exactly at the disk's top. Vector r goes from the disks center to the pint to which the force is applied, so r=(0,rx) . F=(Fx,Fy) . The torque causing rotaion is the xy plane (which is the torque vector's z component...) is equal to rx*Fy-Fx*ry . The force causes both linear and rotational acceleration. The question is how exactly I calculate them. Do I use the same force for both? If not, how do I calculate the accelerations?
Let's say there is a disk in mid-air. There are only 2 dimentions, which is why it's a disk and not a ball...anyway, force is applied to the disk, exactly at the disk's top. Vector r goes from the disks center to the pint to which the force is applied, so r=(0,rx) . F=(Fx,Fy) . The torque causing rotaion is the xy plane (which is the torque vector's z component...) is equal to rx*Fy-Fx*ry . The force causes both linear and rotational acceleration. The question is how exactly I calculate them. Do I use the same force for both? If not, how do I calculate the accelerations?