Force & Work: Understanding the Calculus Behind it All

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Pounds are treated as a unit of force rather than mass because they represent weight, which is the gravitational force acting on an object. The slug is the corresponding unit of mass in the English system. Although the pound has been defined as a unit of mass, it is commonly used to denote force in practical applications. The term "pound-weight" clarifies this distinction, particularly when referring to gravitational force. Understanding this differentiation is crucial for accurately applying concepts of force and work in calculus.
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I am reading over an explanation of Work in my calculus textbook (Early Trancendentals 5e - Stewart). The following example has me confused. Why are pounds treated as a force and not a mass?

http://img71.imageshack.us/img71/8987/forceandwork6ok.jpg
 
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because lbs are a unit of force. the slug is the unit of mass for the english system
 
The pound has actually been officially defined as a unit of mass, even though I believe it was used as a unit of force a long time ago. Nowadays the term pound-weight is used to refer to the gravitational force exerted by a pound, and if you notice the main question states "20-lb weight" to specify this, even though it neglects to be so specific in the rest of the text.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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