Forces and Pressure in a Hydraulic System

AI Thread Summary
In a hydraulic lift problem, the small piston has a diameter of 8.0 cm and the large piston 40 cm, raising a load of 15,000 N. The force required on the small piston is calculated to be 600 N. To find the pressure, the correct formula p=F/A should be applied, using the area of the smaller piston. A user initially struggled with the calculation but later realized a unit conversion error and successfully solved the problem. The discussion highlights the importance of unit consistency in pressure calculations.
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Homework Statement


The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40 cm. The lift raises a load of 15,000 N.

(a) Determine the force that must be applied to the small piston.

(b) Determine the pressure applied to the fluid in the lift.


Homework Equations



p=F/A

The Attempt at a Solution



I correctly solved for part a, and came up with an answer of 600 N. I'm a little unclear about how to obtain the answer for part b. My thought was that since pressure = F/A, I could simply take the pressure I found from part a, and divide by the area of the smaller piston, but I'm not getting the correct answer...

Thanks in advance!
 
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You're doing it correctly. Could the problem be one of units? Pressure is often stated in Newtons/meter^2 (i.e., pascals). Note that 8.0 cm = 0.08 m.
 
EDIT// I must have been making a calculation error. I figured it out.

Thank you!
 
Last edited:
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