- #26

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Seems about right.c= 32.9 N (right?)

Which angle is your A?this how i would solve for the angle of the net force:

SinA / 38.0 N = Sin55° /32.9 N

- Thread starter alexandria
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- #26

- 33,807

- 5,590

Seems about right.c= 32.9 N (right?)

Which angle is your A?this how i would solve for the angle of the net force:

SinA / 38.0 N = Sin55° /32.9 N

- #27

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what do you mean?

- #28

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- #29

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i am aware that using Coordinates system axis is easier, however the lesson that i am doing requires that i learn their method, and it involves the cosine law etc..

they don't provide any other ways to solve and they are expecting me to solve it using their method.

- #30

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And by the way, he meant that A is the angle created by vertical axis or horizontal axis and the forcewhat do you mean?

- #31

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Oh, ok, so if you must use it then magnitude and angle are easy to find but the real problem is the direction of net force.The Vinh

i am aware that using Coordinates system axis is easier, however the lesson that i am doing requires that i learn their method, and it involves the cosine law etc..

they don't provide any other ways to solve and they are expecting me to solve it using their method.

- #32

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Oh and you have a really " cool " teacher

- #33

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You quote the sine formula, but you did not say which angle in the picture is the A in the formula.what do you mean?

It needs to be opposite the side you divide the sine by.

Which angle do you need to find to answer the question?

- #34

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This was the previous diagram i had made, it forms a triangle instead of a parallelogram. I labelled angle A .

SinA / 38.0 N = Sin55° /32.9 N

- #35

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Yes, that looks good.SinA / 38.0 N = Sin55° /32.9 N

- #36

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c = (a^2 + b^2 – 2abcosC) ½

c = ([32.0 N]^2 + [38.0 N]^2 - 2[32.0 N] x [38.0 N]cos55°) ½

c = 32.9 N

SinA/a = SinB/b = SinC/c

SinA / 38.0 N = Sin55° /32.9 N

A = 72 degrees (approx.)

net force = 32.9 N (North 72 degrees East)

does this look right?

- #37

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Draw that direction on your diagram. Does it look right?(North 72 degrees East)

- #38

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is the correct direction (East 72 degrees North)

- #39

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I didn't say your answer was wrong, just asked if it looked reasonable. You should always check that where possible.is the correct direction (East 72 degrees North)

- #40

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the force is pulling the object 72 degrees east of north

- #41

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Ok!oh, ok, so i based the direction of this diagram.

View attachment 97361

the force is pulling the object 72 degrees east of north

- #42

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thank you so much for your help, i really appreciate it :)

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