Forces & Motion: Calculating Avg Acceleration of Hockey Puck

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The discussion revolves around calculating the average acceleration of a hockey puck rebounding from a board, with a focus on understanding two-dimensional motion. The initial attempt to calculate acceleration using a simple formula was incorrect due to the need for directional components. Participants emphasize the importance of breaking down the velocity into north and east components and using trigonometry to determine both acceleration components and the resultant angle. Tips for tackling two-dimensional problems are sought, highlighting a common struggle with visualizing and solving such scenarios. The conversation underscores the necessity of mastering vector decomposition for accurate motion analysis.
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i'm really stuck on this problem:

A Hockey puck rebounds from a board as shown in Figure 16. The puck is in contact with the board for 2.5 ms. Determine the average acceleration of the puck ober the interval
http://img183.imageshack.us/img183/6277/untitled1copyfw2.jpg
 
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Hi, you need to post your thoughts first. Hint- think about the components of the velocities in the north and east directions.
 
ya that's what i can't figure out. I have a hard time seeing the 2 dimensional problems. Since the velocity decreased 5 m/s, i tried a = (5m/s)/(0.0025s) to get the acceleration. that answer was wrong and the correct had a direction, [7.5º N of W]. I tried working backwards from the answer by plugging in the answer in a = v/t so i could see how to solve 2 dimensional problems; i concluded that V = -18.25 m/s over the time interval. Unfontunatley it didn't help me and i still can't see how to solve the problem.
 
What you need to do is figure out the acceleration in the north direction, and also in the east direction. Use trig to find the components of the velocity in each of these directions. Then you can find both components of the acceleration. Then use trig to find the angle, by theta=tan(north component/east component).
 
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